2 B&S Tinned Battery Cable - Twin Sheath

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2 B&S Twin Sheath Tinned Battery Cable

Genuine Australian made TYCAB Twin 2 B&S Tinned battery and starter cable, ideal for use in dual battery systems, caravans or any other auxiliary power application up to 150 amp*


Part # Prefix: C2TS-2

Sheath Colours: Black, Red

Lengths: Cut to length by the metre up to 30m.


 * Refer Specifications and derating factors




AMP Rating at  30°C:150 amp (JASO D609 derating factors apply)

Tycab Code: MWS2399032

Nearest AWG: 2

Strand #/Size: 399/0.32

Nominal Area: 32.00mm²

Insulation Thickness: 1.7mm

Sheath Thickness: 0.96mm

Electrical Resistance at 20°C: 0.61 ohm/km

Nominal O.D.: 13mm×24mm

Mass (kg/100m): 83

Conductor: OXYGEN FREE Tinned Copper Wire to AS/NZS 1125

Insulation: V90 degrees Celsius PVC to AS/NZS 3808


Derating Factors

Derating Factors for Ambient Temperatures °C per JASO D609

As the ambient temperature increases, the current capacity of the cable decreases as per the following chart.

Ambiebt Temperature °C = Derating Factor for Twin 2 B&S 

  • 30°C = 100% capacity (150amp)

  • 40°C = 90% capacity (135amp)

  • 50°C = 76% capacity (114amp)

  • 60°C = 60% capacity (90amp)

  • 70°C = 45% capacity (67.5amp)




  • Battery and starter systems

  • Dual battery systems

  • Caravans and 4WD's

  • Auxiliary power applications

  • Charging systems


Size Guide


Download Sizing Guide







Voltage Drop for Twin 2 B&S Cable: 

To calculate the voltage drop of Twin 2 B&S copper cable, use the following formula:


Voltage Drop = Length x Current x 0.017
                                      Area (32.07)


Length = Total length of cable in metres.

Current = Current draw (amps) through the cable.

Area = Cross sectional area of the copper (in this case 32.07mm²)



  • Formula only applies to copper at 25°C, voltage drop increases with both ambient and cable temperature, at approx 0.4% per °C.

  • 0.017 - This multiplication factor only applies to copper


Example for Twin 2 B&S:

How much voltage drop over 10m of Twin 8 B&S with a current draw of 150A?


  • 10m x 150A x 0.017 = 25.50


Divide this by 32.07 (cross sectional area of 2 B&S - mm²)


  • 25.50/32.07 = 0.795V


You will have a drop of approximatley .08 Volts over the 10m length